How to apply decorators to lambdas?

Question

Is there any syntax for using a decorator on a lambda function in Python? Example:

def simpledecorator(f):
     def new_f():
         print "Using a decorator: "
         f()
     return  new_f

@simpledecorator
def hello():
    print "Hello world!"

Results in this output:

>>> hello()
Using a simple decorator:
Hello world!

Yet when I try the same with a lambda:

@anotherdecorator
f = lambda x: x * 2

I get this:

  File "<stdin", line 2
    f = lambda x: x * 2
    ^
 SyntaxError: invalid syntax

I feel like this might be a good way to make lambdas more versatile by allowing statements to be "injected" into them. But if there exists such a feature, I don't know what the syntax is.

Answer 1

f = anotherdecorator(lambda x: x * 2)