Python Numpy repeating an arange array

Question

so say I do this

x = np.arange(0, 3)

which gives

array([0, 1, 2])

but what can I do like

x = np.arange(0, 3)*repeat(N=3)times

to get

array([0, 1, 2, 0, 1, 2, 0, 1, 2])

Answer 1

EDIT: Refer to hpaulj's answer. It is frankly better.

The simplest way is to convert back into a list and use:

list(np.arange(0,3))*3

Which gives:

>> [0, 1, 2, 0, 1, 2, 0, 1, 2]

Or if you want it as a numpy array:

np.array(list(np.arange(0,3))*3)

Which gives:

>> array([0, 1, 2, 0, 1, 2, 0, 1, 2])