Fast way to store different length Matrix rows into Cell

Question

I have three matrices:

Values = [200x7] doubles
numOfStrings = [82    78    75    73    72    71    70] %(for example)
numOfColumns = [1 4] 

The numOfColumns may contain any set of distinct values from 1 to 7. For example [1 2 3] or [4 7] or [1 5 6 7]. Obviously, biggest numOfColumns that can be is [1 2 3 4 5 6 7].

numOfColumns show the columns I want to get. numOfStrings shows the rows of that columns I need. I.e. in my example I want to get columns 1 and 4. So from the 1 column I want to get the 82 first rows and from the 4th get the 73 first rows.

i.e. if numOfColumns = [1 4] then

myCell{1} = Values( 1:82,1); % Values(numOfStrings(numOfColumn(1)), numOfColumn(1))
myCell{2} = Values( 1:73,4); % Values(numOfStrings(numOfColumn(2)), numOfColumn(2))

P.S. That's not necessary to save it into cell array. If you can offer any another solution Ill be grateful to you.

---

I'm looking for the fastest way to do this, which is likely to be by avoiding for loops and using vectorization.

I think a lot about sub2ind function. But I can't figure out how to return arrays of the different size! Because myCell{1} - [82x1] and myCell{2} - [73x1]. I suppose I can't use bsxfun or arrayfun.

---

RESULTS:

1. Using for loops alike @Will 's answer:

   for jj = 1:numel(numOfColumns)
       myCell{rowNumber(numOfColumns(jj)),numOfColumns(jj)} = Values( 1:numOfStrings(numOfColumns(jj)),numOfColumns(jj));
   end
   

   Elapsed time is 157 seconds

2. Using arrayfun alike @Yishai E 's answer:

   myCell(sub2ind(size(myCell),rowNumber(numOfColumns),numOfColumns)) = arrayfun( @(nOC) Values( 1:numOfStrings(nOC),nOC), numOfColumns, 'UniformOutput', false);
   

   Elapsed time is 179 seconds

3. Using bsxfun alike @rahnema1 's answer:

   idx = bsxfun(@ge,numOfStrings , (1:200).');
   extracted_values = Values (idx);
   tempCell = mat2cell(extracted_values,numOfStrings);
   myCell(sub2ind(size(myCell),rowNumber(numOfColumns),numOfColumns)) = myCell(numOfColumns)';
   

   Elapsed time is 204 seconds

SO, I got a lot of working answers, and some of them are vectorized as I asked, but for loops still fastest!

Answer 1

% Get number of elements in NUMOFCOLUMNS
n = numel(numOfColumns);

% Set up output
myCell = cell(1,n);    

% Loop through all NUMOFCOLUMNS values, storing to cell
for i = 1:n

    myCell{i} = Values(1:numOfStrings(numOfColumns(i)), numOfColumns(i));

end 

Which for your example gives output

myCell = 

[82x1 double]    [73x1 double]