I am using Linux and there is a custom function of which returns an ASCII int
of current key sort of like getch()
. When trying to get used to it and how to store the password I came into an issue, my code is as follows:
int main() {
int c;
char pass[20] = "";
printf("Enter password: ");
while(c != (int)'\n') {
c = mygetch();
strcat(pass, (char)c);
printf("*");
}
printf("\nPass: %s\n", pass);
return 0;
}
Unfortunately I get the warning from GCC:
pass.c:26: warning: passing argument 2 of ‘strcat’ makes pointer from integer without a cast
/usr/include/string.h:136: note: expected ‘const char * __restrict__’ but argument is of type ‘char’
I tried using pointers instead of a char array for pass, but the second I type a letter it segfaults. The function works on its own but not in the loop, atleast not like getch() would on a Windows system.
What can you see is wrong with my example? I am enjoying learning this.
EDIT: Thanks to the answers I came up with the following silly code:
int c;
int i = 0;
char pass[PASS_SIZE] = "";
printf("Enter password: ");
while(c != LINEFEED && strlen(pass) != (PASS_SIZE - 1)) {
c = mygetch();
if(c == BACKSPACE) {
//ensure cannot backspace past prompt
if(i != 0) {
//simulate backspace by replacing with space
printf("\b \b");
//get rid of last character
pass[i-1] = 0; i--;
}
} else {
//passed a character
pass[i] = (char)c; i++;
printf("*");
}
}
pass[i] = '\0';
printf("\nPass: %s\n", pass);
The problem is that strcat
expects a char *
as its second argument (it concatenates two strings). You don't have two strings, you have one string and one char
.
If you want to add c
to the end of pass
, just keep an int i
that stores the current size of pass
and then do something like
pass[i] = (char) c
.
Make sure to null-terminate pass
when you are done (by setting the last position to 0).