I made a spinner with items from MySQL. In MySQL I have got 2 items with the same value. In the spinner I have got 2 duplicates then. When I try to select the second one I get the position of the first one (this is not correct), and when I select the first one I get the position of the first one (this is correct).
Code:
sp.setVisibility(View.VISIBLE);
//BIND
final ArrayAdapter adapter = new ArrayAdapter(c, android.R.layout.simple_spinner_dropdown_item, optochtenarray){
@Override
public View getDropDownView(int position, View convertView, ViewGroup parent) {
View itemView = super.getDropDownView(position, convertView, parent);
if (position == mSelectedIndex) {
itemView.setBackgroundColor(Color.rgb(56,184,226));
}
else {
itemView.setBackgroundColor(Color.TRANSPARENT);
}
return itemView;
}
};
sp.setAdapter(adapter);
//call ID
sp.setOnItemSelectedListener(new AdapterView.OnItemSelectedListener() {
@Override
public void onItemSelected(AdapterView<?> parentView, View view, int position, long id) {
String selectedItem = sp.getSelectedItem().toString();
if (selectedItem != "Kies..."){
//kleur veranderen
mSelectedIndex = sp.getSelectedItemPosition();
Log.e("selectPosition", Integer.toString(mSelectedIndex));
Log.e("ID", idarray.get(position));
//naar de volgende pagina met de 'ID'
Intent myIntent = new Intent(c, gekozenOptocht.class);
myIntent.putExtra("ID", idarray.get(position)); //Optional parameters
c.startActivity(myIntent);
sp.setSelection(adapter.getPosition("Kies..."));
}
}
@Override
public void onNothingSelected(AdapterView<?> parentView) {
// your code here
}
});
Why am I getting the position of the first one when I try to select the second one?
PROBLEM SOLVED! It has something to do with the custom spinner that I had found on the internet.