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swiftuiviewscreenshot

Screenshot of a view without displaying it


I am trying to take a screenshot of a MySecondViewController.view while MyFirstViewController is displayed. I don't want MySecondViewController to appear on the screen at any moment. Is that possible?

Here is my current code inside a function of MyFirstViewController:

func createPreview() {
    let mySecondViewController = self.storyboard!.instantiateViewController(withIdentifier: "MySecondViewController")
    self.navigationController?.pushViewController(mySecondViewController, animated: false)
    let snapshot = mySecondViewController.view.snapshot()
    self.navigationController?.popViewController(animated: false)
}

Here is the UIView extension I am using:

func snapshot() -> UIImage {
    UIGraphicsBeginImageContextWithOptions(bounds.size, false, UIScreen.main.scale)
    drawHierarchy(in: self.bounds, afterScreenUpdates: true)
    let image = UIGraphicsGetImageFromCurrentImageContext()
    UIGraphicsEndImageContext()
    return image!
}

With this code, the snapshot variable contains an invisible picture with the good dimensions. I think it is taking the screenshot after the view has been popped out of the navigation controller.

If I try setting the afterScreenUpdates value to false, then the result is the same. Then, I think it is taking the screenshot before the view has been pushed in the navigation controller.


Solution

  • I've found what I was looking for.

    Here is the new code:

    func createPreview() {
        let mySecondViewController = self.storyboard!.instantiateViewController(withIdentifier: "MySecondViewController")
        let snapshot = mySecondViewController.view.snapshot()
    }
    
    extension UIView {
        func snapshot() -> UIImage {
            UIGraphicsBeginImageContextWithOptions(bounds.size, self.isOpaque, UIScreen.main.scale)
            layer.render(in: UIGraphicsGetCurrentContext()!)
            let image = UIGraphicsGetImageFromCurrentImageContext()
            UIGraphicsEndImageContext()
            return image!
        }
    }