I have multiple lines like this
1480438326593 addons.xpi-utils DEBUG shutdown
and I want to parse them with FINDSTR function from windows CMD.
My problem now is the arguments don't work, or probably I am doing it wrong, but it should work.
I am using this command findstr /V /R ^\d{13} which should use regex and find any digit 13 times at the start of a string.
findstr /V /R ^\d this does work as intended if it starts with a digit but the {13} doesn't work - any help?
To return lines that start with 13 digits use
findstr /r ^[0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9][0-9]
If you want to fail (not match) cases where the 13 digits are followed with more digits (i.e. do not match 12345678901234 more text lines), add \> (trailing word boundary) at the end.
The findstr utility does not support proper regex, only some wildcard patterns, so, there is no limiting quantifier (i.e. {min,max}) support, nor shorthand character classes like \d.
Here is the table of patterns findstr supports:
┌───────────┬─────────────────────────────────────────────────────────────────┐
│ Character │ Value │
├───────────┼─────────────────────────────────────────────────────────────────┤
│ . │ Wildcard: any character │
│ * │ Repeat: zero or more occurrences of previous character or class │
│ ^ │ Line position: beginning of line │
│ $ │ Line position: end of line │
│ [class] │ Character class: any one character in set │
│ [^class] │ Inverse class: any one character not in set │
│ [x-y] │ Range: any characters within the specified range │
│ \x │ Escape: literal use of metacharacter x │
│ \<xyz │ Word position: beginning of word │
│ xyz\> │ Word position: end of word │
└───────────┴─────────────────────────────────────────────────────────────────┘
Note that adding \v option will reverse the results: you will get all lines that do not start with 13 digits.