A premium pizza is comprised of exactly 40 ounces of toppings. There can be multiple entries of each topping, as long as the total weight is equal to 40 ounces.
Pepperoni 4
Sausage 10
Bacon 6
Onion 5
Mushroom 7
For example, a pizza can contain 1 topping of pepperoni, 2 toppings of sausage, 1 topping
of bacon, and 2 toppings of onion : 1*4 + 2*10 + 1*6 + 2*5 = 40 (ounces)
A pizza cannot contain 7 toppings of bacon : 7 * 6 = 42 > 40A pizza cannot contain only 3 toppings of sausage : 3*10 = 30 < 40
Define a rule pizza(P, S, B, O, M) to find out how many of each topping can be contained
on a pizza, where P, S, B, O, and M are the weight (in ounces) of the Pepperoni, Sausage,
Bacon, Onion, and Mushroom toppings respectively.
pizza(P,S,B,O,M):-
member(P,[0,1,2,3,4,5,6,7,8,9,10]),
member(S,[0,1,2,3,4]),
member(B,[0,1,2,3,4,5,6]),
member(O,[0,1,2,3,4,5,6,7,8]),
member(M,[0,1,2,3,4,5]),
S is 4*P + 10*S + 6*B + 5*O + 7*M,
S =:= 40.
I have defined the following rule but it returns false instead of the possible combination of toppings.
You are usingS for both the sausage weight and the weight of the whole pizza.