#include <iostream>
class A {
public:
A() { std::cout << "Constructor" << std::endl; }
A(const A& a) { std::cout << "Copy Constructor" << std::endl; }
A& operator=(const A& a) { std::cout << "Copy = operator" << std::endl; }
A(A&& a) { std::cout << "Move Constructor" << std::endl; }
A& operator=(A&& a) { std::cout << "Move = operator" << std::endl; }
~A() { std::cout << "Destructor" << std::endl; }
};
void f(A&& a) { std::cout << "function" << std::endl; }
int main() {
f(A());
return 0;
}
The output of the following program is:
Constructor
function
Destructor
Why is the move-constructor not called here? It seems like copy elision occurs even if I compile with the flag -fno-elide-constructors: g++ test.cpp -fno-elide-constructors -std=c++11
Short answer: You are not move-constructing anything.
You are just creating a temporary A
object and then passing a reference to it. If you want to see move construction, you could e.g. change the signature of f
to
void f(A a)