Django server stuck on Beanstalkd

Question

I'm trying to setup a django server with existing code. But I seemed to be stuck on this while trying to start server using python manage.py runserver

this the traceback:

(camdyvirtualenv) Mac-mini-3:big-picture-api Sqooge_Ahmed$ python manage.py runserver
Traceback (most recent call last):
  File "manage.py", line 10, in <module>
    execute_from_command_line(sys.argv)
  File "/Users/Sqooge_Ahmed/Documents/Django/camdyvirtualenv/lib/python2.7/site-packages/django/core/management/__init__.py", line 338, in execute_from_command_line
    utility.execute()
  File "/Users/Sqooge_Ahmed/Documents/Django/camdyvirtualenv/lib/python2.7/site-packages/django/core/management/__init__.py", line 303, in execute
    settings.INSTALLED_APPS
  File "/Users/Sqooge_Ahmed/Documents/Django/camdyvirtualenv/lib/python2.7/site-packages/django/conf/__init__.py", line 48, in __getattr__
    self._setup(name)
  File "/Users/Sqooge_Ahmed/Documents/Django/camdyvirtualenv/lib/python2.7/site-packages/django/conf/__init__.py", line 44, in _setup
    self._wrapped = Settings(settings_module)
  File "/Users/Sqooge_Ahmed/Documents/Django/camdyvirtualenv/lib/python2.7/site-packages/django/conf/__init__.py", line 92, in __init__
    mod = importlib.import_module(self.SETTINGS_MODULE)
  File "/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/importlib/__init__.py", line 37, in import_module
    __import__(name)
  File "/Users/Sqooge_Ahmed/Documents/Django/camdyvirtualenv/Camdy-APIs/big-picture-api/bigpicture/settings.py", line 5, in <module>
    from pystalkd.Beanstalkd import Connection as beanstalkdConnect
  File "/Users/Sqooge_Ahmed/Documents/Django/camdyvirtualenv/lib/python2.7/site-packages/pystalkd/__init__.py", line 20, in <module>
    from . import Beanstalkd, Job
  File "/Users/Sqooge_Ahmed/Documents/Django/camdyvirtualenv/lib/python2.7/site-packages/pystalkd/Beanstalkd.py", line 156
    def send_command(self, command, *args, ok_status=None, error_status=None):
                                                   ^
SyntaxError: invalid syntax

Answer 1

In Python 2 you should to set default arguments before *args:

def send_command(self, command, ok_status=None, error_status=None, *args):