SQL query to get the multiple "," positions from a string

Question

I have 5 rows of data like as below

Now I need to find the position of every ',' from my input string.

My output should be like this:

Answer 1

Please try this one it will give output as yours.

Create table #Table (rowNo int identity(1,1), ID varchar(100))
insert into #Table values('32132')
insert into #Table values('32132,32132')
insert into #Table values('32132,32132,6456,654,645')

declare @TableRow int = (select count(*) from #Table),@Tableloop int = 1
while(@Tableloop <= @TableRow)
begin
    Declare @var varchar(100) ;
    SET @var = (select ID from #Table where rowNo=@Tableloop)
    declare @count int = (select len(@var) - len(replace(@var, ',', '')))
    declare @loop int = 1;
    declare @location int = 0;
    print 'Row' + cast(@Tableloop as varchar(5))
    while (@loop <= @count)
    begin
        SET @location = (select charindex(',',@var,@location))
        print cast(@loop as varchar(5)) + ' Comma at ' + cast(@location as varchar(5))
        SET @location = @location +1
        SET @loop = @loop + 1;
    end

    SET @Tableloop = @Tableloop + 1;
END
drop table #Table 

This will show proper output just put it in temp table and display it.