How to separate word by comma, space, period(.), tab(\t), parentheses(), brackets[], and curly braces({}) characters in wordcount hadoop?

I am practicing MapReduce with Cloudera turotial here. However, currently the tutorial only split words by space with this regex in Java:

private static final Pattern WORD_BOUNDARY = Pattern.compile("\\s*\\b\\s*");

However, in addition to space "\\s*", I also want to define separate words by comma, period(.) and tab(\t), parentheses(), brackets[], and curly braces({}) characters. In other words, I define a word as a string that has one or more alphanumeric characters bounded by two non alphanumeric characters. For example:

(cece54) has one word "cece54" bounded by ()
{dwd] has one word "dwd" bounded by {]
xxx) has one word "xxx" bound by <space> and )
so on and so forth.

So how should my regex be written in order to obtain this requirement?

Solution

If you define a word as one or more consecutive alphanumeric characters, then split on one or more consecutive non-alphanumeric characters, i.e. "\\P{Alnum}+" or "[^a-zA-Z0-9]+".

See regex101 for example.

You can prefix the first one with (?U), i.e. "(?U)\\P{Alnum}+", for full international unicode support.