I am working with python dictionary to store the key value pair. I have duplicate keys such as for key 6 there are to values [4,2], [5,1]
, which i can not store in the dictionary since it doesn't allow duplicate keys.
Therefore, I came up with indexing the key itself e.g. for key 7 there are 3 values so I stored them with index as:
{(7, 0): [6, 1], (7, 1): [5, 2], (7, 2): [4, 3]}
Based on above logic I generated the following dictionary:
{
(7, 0): [6, 1],
(7, 1): [5, 2],
(7, 2): [4, 3],
(6, 1): [4, 2],
(6, 0): [5, 1],
(5, 0): [4, 1],
(5, 1): [3, 2],
(3, 0): [2, 1],
(4, 0): [3, 1]
}
My question is that how to find a set of values for a given key e.g. for key 7 I want to get the result as [6,1], [5,2], [4,3]
.
PS: Only python2.7 standard libraries should be used for the solution.
Thanks for your help.
For your answer:
print([v for k,v in d.items() if k[0]==7])
result:
[[6, 1], [5, 2], [4, 3]]
but you're not taking advantage of the dictionary. For your task I would suggest collections.defaultdict
with list
as default argument
Demo:
import collections
d = collections.defaultdict(list)
d[7].append([6,1])
d[7].append([5,2])
d[7].append([4,3])
print(d[7])
result:
[[6, 1], [5, 2], [4, 3]]