I am trying to create a feedback using apex_util.submit_feedback
procedure within APEX application.
apex_util.submit_feedback (
p_comment => :P102_FEEDBACK,
p_type => :P102_FEEDBACK_TYPE,
p_application_id => :P102_APPLICATION_ID,
p_page_id => :P102_PAGE_ID,
p_email => null);
My query is how can I refer to the newly created feedback record?
Is there any out parameter which returns feedback Id? I have searched on oracle documentation but no info about how to get feedback id.
Looking at APEX 4.2 (I don't have 5.0 installed) the feedback table WWV_FLOW_FEEDBACK has a trigger WWV_FLOW_FEEDBACK_T1 that does this:
if inserting and :new.id is null then
:new.id := wwv_flow_id.next_val;
end if;
So it may be that you can get the ID of the feedback immediately after you call apex_util.submit_feedback
like this:
new_feedback_id := wwv_flow_id.curr_val;
However, it is possible that apex_util.submit_feedback
sets the ID explicitly from some other sequence, in which case the trigger will not set it. It should be easy to test a few times and check.
Bear in mind that even if this does work now, there is no guarantee that Oracle won't change the way it works in a future release of APEX and break your code!