Checking if a char is pressed

Question

The program should read 2 ints and calculate the sum or product depending on the symbol introduced from the keyboard. If you press q at any given momement, it must exit.

#include "stdafx.h"
#include <iostream>
#include<conio.h>

using namespace std;

int main()
{

char k, l ='h',c;     
int a,b,s, p;             

aici: while (l != 'q')
{

    cin >> a;


    if (_kbhit() == 0) //getting out of the loop
    {
        c = a;
        if (c == 'q')
        {
            l = 'q';
            goto aici;
        }
    }


    cin >> b;

    if (_kbhit() == 0)
    {
        c = b;
        if (c == 'q')
        {
            l = 'q';
            goto aici;
        }
    }


    k = _getch();

    if (_kbhit() == 0)
    {
        c = k;
        if (c == 'q')
        {
            l = 'q';
            goto aici;
        }
    }


    if (k == '+')
    {

        s =(int)(a + b);
        cout << s;
    }
    if (k == '*')
    {
        p = (int)(a*b);
        cout << p;
    }
}
return 0;
}

It expects both a and b to be ints so typing 'q' makes a total mess. Is it possible to make the program work without having a and b declared as chars?

Answer 1

You don't need to use goto and kbhit() inside cin. a simple way is:

#include <iostream>
#include <string>

using namespace std;

int main()
{
    int a,b;
    string A, B
    char k;

    while(1)
    {
        cin >> A;
        if(A == "q") break;
        cin >> B;
        if(B == "q") break;

        a = atoi(A.c_str());
        b = atoi(B.c_str());

        cin >> k;
        if(k == 'q') break;

        if (k == '+')
            cout << (a + b);
        if (k == '*')
            cout << (a*b);

    }
}