I'm trying to create a program that prompts users to enter their grade, and then compares that value, x, in a series of nested If-Else statements:
x = int(input("What is your grade?"))
def grade(x):
if x >= 90:
return "A"
else:
if x >= 80:
return "B"
else:
if x >= 70:
return "C"
else:
if x >= 60:
return "D"
else:
return "F"
print( "Grade:", grade(x))
When I try to run this program, I get an error message:
ParseError: bad input on line 4
What's wrong with:
if x >= 90:
?
So far I haven't been able to get the dialogue box to show up asking for the user to enter their grade because of this error.
EDIT: After fixing indentation and using Elif
x = int(input("What is your grade?"))
def grade(x):
if x >= 90:
return "A"
elif:
x >= 80:
return "B"
elif:
x >= 70:
return "C"
elif:
x >= 60:
return "D"
else:
return "F"
print( "Grade:", grade(x))
Still gives me a syntax error:
SyntaxError: invalid syntax (<string>, line 7).
If you're using nested else-if, I suggest you use elif
x = int(input("What is your grade?"))
def grade(x):
if x >= 90:
return "A"
elif x >= 80:
return "B"
elif x >= 70:
return "C"
elif x >= 60:
return "D"
else:
return "F"
print( "Grade:", grade(x))
Input: What is your grade? 10
Output: F
And be careful about indented blocks!
And here is syntax if you are unclear with it.
if expression1:
statements
elif expression2:
statements
elif expression3:
statements
else:
statements