Borland C++ 5.02 cout not showing on the console window

Question

I'm sorry for this newbie question, i tried to make this program using borland 5.02, but for some reason the cout in the if (stat) isn't showing on the console window when i write married. I don't know what's wrong and i've been stuck for hours. please help me

#include <stdio.h>
#include <conio.h>
#include <iostream.h>

int main()
{
   int NIP, GOL, GP, TI, TA, JA, TG ;
   char NM[20], STAT[10] ;

   cout << "ID Number : " ;
   cin >> NIP ;

   cout << "Name : " ;
   cin >> NM ;

   cout << "Faction : " ;
   cin >> GOL ;

   if (GOL == 1)
   {
    GP = 1500000 ;
   }
   else if (GOL == 2)
   {
    GP = 2000000 ;
   }
   else
   {
    GP = 2500000 ;
   }

   cout << "Status  : " ;
   gets (STAT) ;

   if (STAT == "Married" || STAT == "married")
   {
      cout << "Number of children : " << endl ;
      cin >> JA ;
      TI = 0.05 * GP ;

      if (JA <= 3)
      {
        TA = 0.02 * GP * JA ;
      }
      else
      {
        TA = 0.02 * GP * 3 ;
      }
   }
   else
   {
    TI = 0 ;
    TA = 0 ;
   }

   TG = GP + TI+ TA ;

   cout << endl << "-Results-" << endl ;
   cout << "Your GP: " << GP << endl ;
   cout << "Your TI: " << TI << endl ;
   cout << "Your TA: " << TA << endl ;
   cout << "Your TG: " << TG << endl ;

   getch () ;

}

Update : i have tried to change the gets(STAT) ; to cin >> STAT ; before but it doesn't seem to have any effect. the program looked like this when i run them

---

ID Number : 0123141421

Name : Vykmon

Faction : 1

Status : married (Here is the problem)

-Results-

Your GP: 1500000

Your TI: 0

Your TA: 0

Your TG: 1500000

---

Even though i have write married on the status, the cout << "Number of children : " << endl ; didn't show up on console window. it as if the if (STAT == "Married" || STAT == "married") aren't working, and the "Status: married" count as

else
   {
    TI = 0 ;
    TA = 0 ;
   }

Answer 1

STAT == "Married" would work in standard C++ if STAT were a std::string.

However, it's an array of char, and that means that you're comparing two pointers. Because C++ doesn't support direct comparison of arrays. So each of the two array expressions decay to pointer to first item.

And these pointers are guaranteed to be different.

---

Note 1: Borland C++ 5.02 sounds like mid 1990's, before the first C++ standard. There are a host of free modern compilers. The three most well known are g++, clang and Visual C++ (the latter is only available for the PC platform).

Note 2: As I recall the std::string in Borland C++ was totally botched. If just using std::string doesn't work, consider using strcmp to compare C strings (like the arrays you have).

Note 3: In standard C++ (since the first standard in 1998) there is no <iostream.h> header. Instead include <iostream>, and possibly add a using namespace std;. Or appropriate using directives, or qualifications of names like cout and endl, i.e. writing std::cout and std::endl.

---

In other news:

• By reserving SHOUTCASE names for macros, you can ease the code reading experience significantly, and avoid unintended text substitutions to boot. Not to mention conforming to the common convention about this.

• By using getline instead of >>, the program can read a name with a space in it. However, this only works nicely when the input buffer is empty (since getline doesn't skip whitespace). So, it's something to consider, but it can involve some work.