I am currently trying to use a "wine" command from my PHP-Script.
If i execute this:
$shell = shell_exec("/usr/bin/wine --version");
All is working fine and WINE version is displayed in $shell.
But, if i try to make it like this:
$run = shell_exec("/usr/bin/wine ".$workdir."/bin/tool.exe -m ".$workdir."/bin/std.maps -a ".$workdir."/bin/alias.file -n ".$workdir."/files/".$project_name."/upload/dump.bin -o ".$workdir."/files/".$project_name."/maps/definitions.list");
Which results in:
$run = shell_exec("/usr/bin/wine /var/www/html/bin/tool.exe -m /var/www/html/bin/std.maps -a /var/www/html/bin/alias.file -n /var/www/html/files/1-59374-94700/upload/dump.bin -o /var/www/html/files/1-59374-94700/maps/definitions.list 2>&1");
I get the following output:
wine: chdir to /.wine : No such file or directory
What i am doing wrong? If i enter the command above directly to the shell, all is working fine. If i do it without /usr/bin/ in front of wine, the output's are the same.
Br, Chris
I haven't try it myself but I think it is because wine is run as different user with different environment settings. Try create .wine directory inside /var/www and make www-data user as owner of this directory and make /var/www/.wine HOME directory.
$run = shell_exec("HOME=/var/www/.wine /usr/bin/wine ".$workdir."/bin/tool.exe -m ".$workdir."/bin/std.maps -a ".$workdir."/bin/alias.file -n ".$workdir."/files/".$project_name."/upload/dump.bin -o ".$workdir."/files/".$project_name."/maps/definitions.list");