I wrote this code to take input from the command line, and depending on the input, will perform a set of actions, or if the input is incorrect, throws an error. However, I also need to check if no arguments are supplied, which I try to account for in my else statement.
if(strcmp(argv[1], "-L") == 0)
{
//does stuff
}
else if(strcmp(argv[1], "-W") == 0)
{
//does stuff
}
else if (*(argv[1]) != 1)
{
puts("error: invalid input");
}
else //should check if no arguments
{
puts("error: expected command line argument");
return 1;
}
I am getting a segmentation fault whenever there are no arguments from the command line, and I'm not sure how to fix it. I have also tried to write the else statement this way:
else if(argc < 2)
{
puts("error: expected command line argument");
return 1;
}
This was based on my previous research on here where I found "C produce error if no argument is given in command line," but it won't work either. I am a beginner in C and do not fully understand argc and argv, so if anyone has any suggestions or logic I'm completely overlooking, please let me know.
You need to check if argc < 2 before anything else.
Else you get segmentation fault because argv[index] could be something you have not privileges to access.