Java bean validation uppercase letters with range

Question

I have a some issue with pattern for java bean validation. I have a pattern for my variable inside java class

@Pattern(regexp = ".*[A-Z]+[[A-Z]\\p{Space}]+[A-Z\\p{Punct}]+([0-9]{1,10})?", message = "Error")*
private String name;

And actually it's working, but now I have to add a range {0,32} to uppercase words. When I added [A-Z]{0,32} it breaks down

The name should fit values below

1. PROFILE - true
2. P - true
3. PRO - true
4. PROFILEPROFILEPROFILEPROFILEPROF - true
5. PROFILEPROFILEPROFILEPROFILEPROFI - false
6. profilename - false
7. PROFILE1 - true
8. PROFILE100 - true
9. PROFILE1000 - true
10. PROFILE1000000 - true
11. 1111 - false
12. PROFILEPROFILE123456789PROFILE123 - false
13. profile_name - false
14. *^^@ - false
15. PROFILE NAME - true
16. PROFILE_NAME - true
17. PROFILE. - true
18. &)12p - false
19. 11PROFILE - true
20. 1234PROFILE - true
21. $%#PROFILE - true
22. nothing - false

How to change/refactor that pattern to possible to add range for uppercase letter and 2, 5, 12 would working?

The solution is "(?=.*[A-Z])[\p{Punct}A-Z0-9 ]{1,32}"

Answer 1

You may use

@Pattern(regexp = "(?=.*[A-Z])[\\p{Punct}A-Z0-9 ]{1,32}", message = "Error")

See the regex demo

Since the pattern is anchored by default (it is used with .matches() method), no ^ and $ are necessary around the pattern.

It matches:

• (?=.*[A-Z]) - after any 0+ chars other than linebreak chars there must be at least 1 uppercase ASCII letter
• [\\p{Punct}A-Z0-9 ]{1,32} - match 1 to 32 uppercase ASCII letters, digits, space or chars from the Punct POSIX character class (it includes punctuation and symbols).