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pythonpython-3.xbrute-forcecracking

How to create a brute-force password cracker for alphabetical and alphanumerical passwords?


I'm trying to create a brute force Python code for alphabetical and alphanumerical combinations and have it report the password and amount of time it took.

For numerical combinations I made this:

import datetime as dt

Password4 = 123456

def crack_password():
    start = dt.datetime.now()
    for n in range(1000000):
        password_guess = '{0:04d}'.format(n)
             if password_guess == str(Password4):
                end = dt.datetime.now()
                print("Password found: {} in {}".format(password_guess, end - start))
               break
    guesses = crack_password()

For alphanumerical combinations (does not work) I tried:

import random

letters = [str(i) for i in range('a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p')]
s = [''.join([a,b,c,d,e,f,g,h]) for a in letters for b in letters for c   in letters for d in letters for e in letters for f in letters for g in letters  for h in letters]
random.shuffle(s)
real_password = 'aaaaaaaa'
i = 0

for code in s:
if code == real_password:
    print()
        print('The password is: ', code)
        break
    else:
        i += 1
        print(i, ' failures', end='\r')

It should report either number of attempts or time it took.


Solution

  • Here's a naiive brute force method that will guess numbers (string.digits) and lower case letters (string.ascii_lowercase). You can use itertools.product with repeat set to the current password length guessed. You can start at 1 character passwords (or whatever your lower bound is) then cap it at a maximum length too. Then just return when you find the match.

    import itertools
    import string
    
    def guess_password(real):
        chars = string.ascii_lowercase + string.digits
        attempts = 0
        for password_length in range(1, 9):
            for guess in itertools.product(chars, repeat=password_length):
                attempts += 1
                guess = ''.join(guess)
                if guess == real:
                    return 'password is {}. found in {} guesses.'.format(guess, attempts)
                # uncomment to display attempts, though will be slower
                #print(guess, attempts)
    
    print(guess_password('abc'))
    

    Output

    a 1
    b 2
    c 3
    d 4
    ...
    aba 1369
    abb 1370
    password is abc. found in 1371 guesses.