How to select only the second max date from a table

Question

I have a table where the delivery date and order number are stored.

Here i was able to get the order with the max delivery date.

SELECT DISTINCT D.ORDER_NO
FROM DELIVERY D
WHERE D.CUSTOMER_NO =112 AND D.DELIVERY_DATE = (SELECT  MAX(D1.DELIVERY_DATE) FROM DELIVERY D1
WHERE D1.CUSTOMER_NO = 112 );

Here a single customer may have multiple orders.

Now what i want is to get only the second max date.

By using the above query I was able to get the list of data other than the max delivery date by changing the = to < and adding ORDER BY in the subquery.

But its an entire list but i want only the second max date.

Someone pls tell me how I can get only the second max date.

Note: I have tried using ROWNUM<=1 but i am getting wrong date

Answer 1

SELECT D.ORDER_NO
FROM
(
SELECT DISTINCT D.ORDER_NO,D.DELIVERY_DATE,ROW_NUMBER()OVER(order by D.DELIVERY_DATE desc) RowNo
FROM DELIVERY D
WHERE D.CUSTOMER_NO =1128158 
ORDER BY D.DELIVERY_DATE DESC)
t WHERE t.RowNo = 2;