consider the pd.DataFrame
df
df = pd.DataFrame([
[1, 2, 3, 4, 5],
[5, 1, 2, 3, 4],
[4, 5, 1, 2, 3],
[3, 4, 5, 1, 2],
[2, 3, 4, 5, 1]
], list('abcde'), list('ABCDE'))
How do I align the diagonal values into columns?
I'd like this as the result
i've done this
pd.DataFrame([np.roll(row, -k) for k, (_, row) in enumerate(df.iterrows())],
df.index, df.columns)
I'm hoping for something more straight forward.
You can use numpy solution - for shift is used reversed Series
same length as DataFrame
(if DataFrame
has non numeric and non monotonic index it works nice also):
A = df.values
r = pd.Series(range(len(df)))[::-1] + 1
rows, column_indices = np.ogrid[:A.shape[0], :A.shape[1]]
r[r < 0] += A.shape[1]
column_indices = column_indices - r[:,np.newaxis]
result = A[rows, column_indices]
print (pd.DataFrame(result, df.index, df.columns))
A B C D E
a 1 2 3 4 5
b 1 2 3 4 5
c 1 2 3 4 5
d 1 2 3 4 5
e 1 2 3 4 5