Here is my code:
import random
listx = []
ready = 0
listy = []
listz = []
#function
def function(r,s,q):
listy=[]
if len(listx)==4 or len(listx)==8:
listy.append((listx, t))
print "y", listy
# here it starts:
for t in range(1,25):
randomnumber = random.uniform(0.0, 1.0)
if randomnumber <= 0.5:
listx.append((t))
print "x", listx
if ready == 0: #condition, lets say: ready is always 0
function(5,6,8) #this function generates listy from input of listx
if listy != 0: #if listy is not empy anymore, fill listz with items of listy
listz.append(listy)
del listy
print "z", listz
I have 3 lists; listx
, listy
and listz
. I generate random numbers to listx
. If ready==0
(always) I call the function (function(r,s,q))
. If a condition (len==4 or 8)
is met, the items in the list are appended to listy.
At this point, I would like to add these numbers from listy
to listz
and leave listy
empty again. The items that I transported from listy
to listz
should be removed from listx
.
Does anyone know how to solve this?
I think this may do you want. Changes to your code are indicated with # UPPERCASE COMMENTS
.
import random
listx = []
ready = 0
listy = []
listz = []
#function
def function(r,s,q):
global listy #### ADDED
listy=[]
if len(listx) in (4, 8): # STREAMLINED
listy.append((listx, t))
print "y", listy
# here it starts:
for t in range(1,25):
randomnumber = random.uniform(0.0, 1.0)
if randomnumber <= 0.5:
listx.append((t))
print "x", listx
if ready == 0: # condition, lets say: ready is always 0
function(5,6,8) # this function generates listy from input of listx
#### REWRITTEN
if listy: # not empty?
listz += listy[0][0] # copy numbers from listy to listz
del listx[:len(listy[0][0])] # remove numbers transported from listx
del listy # empty listy
print "z", listz