I wish to jump to a line, either in same context, or outside the function. I've got a "test.c"
1
2 #include<stdio.h>
3 void fa(int c)
4 {
5 printf("begin\n");/*I break here*/
6 printf("%d\n",c); /*I wish to jump 1 line here*/
7 }
8 void fb(){}
9
10 int main(){
11 int b=1;
12 int i=2;
13 fa('a');
14 fb(); /*I also want to jump here*/
15 return 0;
16 }
Then compiled it with gcc test.c -g
and run it using gdb a.out
.
gdb a.out
GNU gdb (Ubuntu 7.11.1-0ubuntu1~16.04) 7.11.1
...
(gdb) b 5
Breakpoint 1 at 0x400571: file test.c, line 5.
(gdb) r
Starting program: /home/Troskyvs/a.out
Breakpoint 1, fa (c=97) at test.c:5
5 printf("begin\n");
(gdb) j 6
Continuing at 0x40057b.
97 # This line is odd!
[Inferior 1 (process 6583) exited normally]
(gdb) f
No stack. # Why it doesn't print line 6 source code
(gdb) j 14
The program is not being run.
# What happen here?
I also tried "jump +1" and "jump +14". Same result, don't work.
How "jump" could work in my way?
Well, it's doing what you asked it to do. It
printf("%d\n",c);
, printed the value (97). See here to know why the value is 97
[Inferior 1 (process 6583) exited normally]
So, your program is over already. It's no longer running.
FWIW, if you want to stop/interrupt the normal the execution again, you have to set more that one break point after the jump destination to make it wait.