How to launch terminal and pass it a command programatically? | Swift3, macOS

Question

So my code so far looks like this:

import Foundation
import AppKit

print("Starting")
let base = NSWorkspace()

print("Launching Terminal")
base.launchApplication("Terminal") //launches terminal

print("Terminating terminal")
let apps = base.runningApplications
for app in apps {

    if app.localizedName == "Terminal" {
        print(app.localizedName)

        app.terminate() //Terminate
        break
    }
}

I have figured out how to start terminal and then how to close it, but I don't know how to pass it a command. The command I want to pass it is: "screencapture ~/Desktop/screenshot.jpg"

Answer 1

As Martin suggested this executes screencapture ~/Desktop/screenshot.jpg in Swift 3

let fileURL = try! FileManager.default.url(for: .desktopDirectory, in: .userDomainMask, appropriateFor: nil, create: false)
Process.launchedProcess(launchPath: "/usr/sbin/screencapture", arguments: [fileURL.appendingPathComponent("screenshot.jpg").path])

The way to get the URL to the desktop folder works only in non-sandboxed apps.