This issue is asked already some times. But in the application of google apps script i can't solve this problem.
function two ()
{
var bridgeclubs = SpreadsheetApp.openById("1dfyI1jbz..........TVg4OoixKTz1");
var bridgeclubs_sheet = bridgeclubs.getSheetByName("Sheet1");
var data_bridgeclubs = bridgeclubs_sheet.getDataRange().getValues();
var numRows = bridgeclubs_sheet.getDataRange().getNumRows();
var sprshtname = SpreadsheetApp.getActiveSpreadsheet().getName();
for (var i=1; i<=numRows; i++)
{
if (sprshtname == data_bridgeclubs[i][6])
{
var A = i;
break;
}
}
}
In function one I do a call to function two, where I need this value A:
function one ()
{
two ();
//here I need this value A;
var C= 35 * A;for instance
}
Who can help me?
You can return value from function using return i;
and obtain it in within one
by var A = two();
.
function two() {
var bridgeclubs = SpreadsheetApp.openById("1dfyI1jbz..........TVg4OoixKTz1");
var bridgeclubs_sheet = bridgeclubs.getSheetByName("Sheet1");
var data_bridgeclubs = bridgeclubs_sheet.getDataRange().getValues();
var numRows = bridgeclubs_sheet.getDataRange().getNumRows();
var sprshtname = SpreadsheetApp.getActiveSpreadsheet().getName();
for (var i=1; i<=numRows; i++) {
if (sprshtname == data_bridgeclubs[i][6]) {
return i;
}
}
}
function one() {
var C;
var A = two();
if (A) {
C = 35 * A;
}
}