I am having trouble writing an algo in r, in python this wouldnt be a big deal but r's syntax has thrown me off. I would like to set the first index of z and nums equal to eachother and put it into a list. Once in a list I would like to print the letter of a negative number. Then i would like to print the numbers that correspond to j k l.
nums<-c(1.0, 3.0, -2, 8, -4, 4, 2, -3, 9, 1, 4, 2, 2, 1, 8, 2)
z<-c("a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p")
lets<-c(j,k,l)
for (i in nums){
for(j in z) {
}}
list=((a,1),(b,3),(c,-2),(d,8),(e,-4),(f,4),(g,2),(h,-3),(i,9),(j,1),(k,4),(l,2),(m,2),(n,1),(o,8),(p,2))
negative=c,e,h,
letters=1,4,2
What you could do is (using your data):
df <- data.frame(z,nums, stringsAsFactors = FALSE)
There all the letters and nums in
> df
z nums
1 a 1
2 b 3
3 c -2
4 d 8
5 e -4
6 f 4
7 g 2
8 h -3
9 i 9
10 j 1
11 k 4
12 l 2
13 m 2
14 n 1
15 o 8
16 p 2
And then you can access what ever you want:
df$z[df$nums<0]
Results in:
[1] "c" "e" "h"
And to get the number for j,k,l you can use grepl:
df[grepl("[j,k,l]", df$z),]
z nums
10 j 1
11 k 4
12 l 2
Then you have again a sub data frame or for just the numbers do:
df$nums[grepl("[j,k,l]", df$z)]
[1] 1 4 2