Display enum value based on field value

Question

I want to return a enum value based on a field value.

For example:

If Free value field has the value '15', I want to return the enum value "1", because the Label of enum value 1 is: '10-20', because 15 is in the range of 10-20 I want to return that value.

I want to create a display method for this.

I guess I can accomplish this with a switch case scenario.
How can I best set this up?

Answer 1

Of course you can do it with a switch / case but if you deal with a range of values and a limited set of result values (your enumeration elements) then a simple if / else if is probably better suited

So instead of stating each possible value (1, 2, 3, 4 bla bla) in your case branches do something like this

int x;
;

x = yourTable.YourField;
if (x >= 1 && x <= 15)
{
    return YourEnum::1to15;
}
else if (x >= 16 && x <= 20)
{
    return YourEnum::16to20;
}
// other possible ranges
else
{
    throw YourEnum::Unknown;
}