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pythonpython-2.7ioreadfile

Read multiple lines from a file batch by batch


I would like to know is there a method that can read multiple lines from a file batch by batch. For example:

with open(filename, 'rb') as f:
    for n_lines in f:
        process(n_lines)

In this function, what I would like to do is: for every iteration, next n lines will be read from the file, batch by batch.

Because one single file is too big. What I want to do is to read it part by part.


Solution

  • itertools.islice and two arg iter can be used to accomplish this, but it's a little funny:

    from itertools import islice
    
    n = 5  # Or whatever chunk size you want
    with open(filename, 'rb') as f:
        for n_lines in iter(lambda: tuple(islice(f, n)), ()):
            process(n_lines)
    

    This will keep isliceing off n lines at a time (using tuple to actually force the whole chunk to be read in) until the f is exhausted, at which point it will stop. The final chunk will be less than n lines if the number of lines in the file isn't an even multiple of n. If you want all the lines to be a single string, change the for loop to be:

        # The b prefixes are ignored on 2.7, and necessary on 3.x since you opened
        # the file in binary mode
        for n_lines in iter(lambda: b''.join(islice(f, n)), b''):
    

    Another approach is to use izip_longest for the purpose, which avoids lambda functions:

    from future_builtins import map  # Only on Py2
    from itertools import izip_longest  # zip_longest on Py3
    
        # gets tuples possibly padded with empty strings at end of file
        for n_lines in izip_longest(*[f]*n, fillvalue=b''):
    
        # Or to combine into a single string:
        for n_lines in map(b''.join, izip_longest(*[f]*n, fillvalue=b'')):