How to clone multiple inheritance object?

Question

I have defined a Cloneable interface:

struct Cloneable
{
  virtual Cloneable * clone(void) const = 0;
}

I have also some other interface classes (content not relevant to issue):

struct Interface
{
};

struct Useful_Goodies
{
};

I have created a leaf object which inherits from the above classes:

struct Leaf : public Cloneable, public Interface, public Useful_Goodies
{
  Leaf * clone(void) const  // Line #1 for discussion.
  {
     return new Leaf(*this);
  }
};

I'm getting the error:

overriding virtual function return type differs and is not covariant from 'Cloneable::clone'

If I change the type to Cloneable *, I get this error message:

'return' : ambiguous conversions from 'Leaf *' to 'Cloneable *'

My Questions (all related):

1. How can the leaf class resolve the requirements of the Cloneable interface?
2. Is there a better solution to implement a Cloning contract, where all objects are guaranteed to implement cloning?

I'm using this paradigm as part of generic programming (records, fields & database).

Compiler: MS Visual Studio 2008; Platforms: Windows XP & Vista

Answer 1

Having your clone function return a Cloneable * is correct.

You will get an ambiguous conversion if one of your interfaces also derives from Cloneable.

Edit: Alf points out in the comments that not only is it possible for Leaf::clone to return a Leaf*, it's actually preferable for it to do so. I stand corrected.