I have a directory of 9 images:
image_0001, image_0002, image_0003 image_0010, image_0011 image_0011-1, image_0011-2, image_0011-3 image_9999
I would like to be able to list them in an efficient way, like this (4 entries for 9 images):
(image_000[1-3], image_00[10-11], image_0011-[1-3], image_9999)
Is there a way in python, to return a directory of images, in a short/clear way (without listing every file)?
So, possibly something like this:
list all images, sort numerically, create a list (counting each image in sequence from start). When an image is missing (create a new list), continue until original file list is finished. Now I should just have some lists that contain non broken sequences.
I'm trying to make it easy to read/describe a list of numbers. If I had a sequence of 1000 consecutive files It could be clearly listed as file[0001-1000] rather than file['0001','0002','0003' etc...]
Edit1(based on suggestion): Given a flattened list, how would you derive the glob patterns?
Edit2 I'm trying to break the problem down into smaller pieces. Here is an example of part of the solution: data1 works, data2 returns 0010 as 64, data3 (the realworld data) doesn't work:
# Find runs of consecutive numbers using groupby. The key to the solution
# is differencing with a range so that consecutive numbers all appear in
# same group.
from operator import itemgetter
from itertools import *
data1=[01,02,03,10,11,100,9999]
data2=[0001,0002,0003,0010,0011,0100,9999]
data3=['image_0001','image_0002','image_0003','image_0010','image_0011','image_0011-2','image_0011-3','image_0100','image_9999']
list1 = []
for k, g in groupby(enumerate(data1), lambda (i,x):i-x):
list1.append(map(itemgetter(1), g))
print 'data1'
print list1
list2 = []
for k, g in groupby(enumerate(data2), lambda (i,x):i-x):
list2.append(map(itemgetter(1), g))
print '\ndata2'
print list2
returns:
data1
[[1, 2, 3], [10, 11], [100], [9999]]
data2
[[1, 2, 3], [8, 9], [64], [9999]]
Here is a working implementation of what you want to achieve, using the code you added as a starting point:
#!/usr/bin/env python
import itertools
import re
# This algorithm only works if DATA is sorted.
DATA = ["image_0001", "image_0002", "image_0003",
"image_0010", "image_0011",
"image_0011-1", "image_0011-2", "image_0011-3",
"image_0100", "image_9999"]
def extract_number(name):
# Match the last number in the name and return it as a string,
# including leading zeroes (that's important for formatting below).
return re.findall(r"\d+$", name)[0]
def collapse_group(group):
if len(group) == 1:
return group[0][1] # Unique names collapse to themselves.
first = extract_number(group[0][1]) # Fetch range
last = extract_number(group[-1][1]) # of this group.
# Cheap way to compute the string length of the upper bound,
# discarding leading zeroes.
length = len(str(int(last)))
# Now we have the length of the variable part of the names,
# the rest is only formatting.
return "%s[%s-%s]" % (group[0][1][:-length],
first[-length:], last[-length:])
groups = [collapse_group(tuple(group)) \
for key, group in itertools.groupby(enumerate(DATA),
lambda(index, name): index - int(extract_number(name)))]
print groups
This prints ['image_000[1-3]', 'image_00[10-11]', 'image_0011-[1-3]', 'image_0100', 'image_9999'], which is what you want.
HISTORY: I initially answered the question backwards, as @Mark Ransom pointed out below. For the sake of history, my original answer was:
You're looking for glob. Try:
import glob
images = glob.glob("image_[0-9]*")
Or, using your example:
images = [glob.glob(pattern) for pattern in ("image_000[1-3]*",
"image_00[10-11]*", "image_0011-[1-3]*", "image_9999*")]
images = [image for seq in images for image in seq] # flatten the list