I have two exe's. One should be started as a server and open a pipe for interaction. Another would connect through this win pipe and run testing requests to it.
The problem is that after when I try to start programm1.exe in appveyor.yml script, I see no output and further instructions not being executed.
I need smth like this:
start programm1.exe --options
start programm2.exe --options
set output of programm2 to appveyor log
wait until programm2 finished
stop programm1
If you know how to do this, please share your experience, thanks!
You can use Start-Process
and Stop-Process
cmdlets to do that. You need to save started process information in variable to be able to stop it.
Here are how commands can look in appveyor.yml style:
install:
- ps: $MyProcess = Start-Process notepad.exe -PassThru
on_finish:
- ps: Stop-Process -Id $MyProcess.Id
Hope this helps.
--ilya