I have a value of type Seq[Array[Int]]
and I want to end up with a single Array[Int]
. I thought foldLeft would work, but surprisingly it doesn't:
scala> val arr1 = Array(1,2,3)
arr1: Array[Int] = Array(1, 2, 3)
scala> val arr2 = Array(4,5,6)
arr2: Array[Int] = Array(4, 5, 6)
scala> val seq = Seq( arr1, arr1 )
seq: Seq[Array[Int]] = List(Array(1, 2, 3), Array(1, 2, 3))
scala> seq.foldLeft ( Array.empty )( (x,y) => x ++ y )
<console>:17: error: value ++ is not a member of Array[Nothing]
seq.foldLeft ( Array.empty )( (x,y) => x ++ y )
^
That error doesn't seem like the entire truth though because I can do this:
scala> Array.empty
res22: Array[Nothing] = Array()
scala> Array.empty ++ arr1 ++ arr2
res23: Array[Int] = Array(1, 2, 3, 4, 5, 6)
What gives?
What about seq.flatten.toArray
?
For foldLeft
solution you should tell type to compiler: Array.empty[Int]
, when you missed that [Int]
, the compiler chose Nothing
as the only possible type for Array.empty
.