I need to translate a link like <a ref="123.pdf"> to a link where the filesize is present, like <a ref="123.pdf" size="22Kb">. The pdf's are present in the folder that contains the inputfile. Is there a way to do that with xslt 2.0? Can someone point me in the right direction?
Thanks!
Assuming you can use the commercial editions (i.e. PE or EE) of Saxon 9 or any other XSLT 2.0 processor that supports the EXPath file module you can use it as follows:
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:file="http://expath.org/ns/file"
exclude-result-prefixes="xs file"
version="2.0">
<xsl:template match="@* | node()">
<xsl:copy>
<xsl:apply-templates select="@* | node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="a/@href[file:exists(resolve-uri(., base-uri()))]">
<xsl:copy/>
<xsl:attribute name="size" select="concat(file:size(resolve-uri(., base-uri())) idiv 1024, 'KB')"/>
</xsl:template>
</xsl:stylesheet>
Using Saxon that transforms
<root>
<a href="test2016082601.pdf">doc</a>
</root>
into
<root>
<a href="test2016082601.pdf" size="141KB">doc</a>
</root>