I have a vector and I would like to extract all the blocks from it:
x = [1 1 1 4 4 5 5 4 6 1 2 4 4 4 9 8 4 4 4 4]
so that I will get vectors or a cell containing the blocks:
[1 1 1], [4 4], [5 5], [4], [6], [1], [2], [4 4 4], [9], [8], [4 4 4 4]
Is there an efficient way to do it without using for loops? Thanks!
You can use accumarray
with a custom anonymous function:
y = accumarray(cumsum([true; diff(x(:))~=0]), x(:), [], @(x) {x.'}).';
This gives a cell array of vectors. In your example,
x = [1 1 1 4 4 5 5 4 6 1 2 4 4 4 9 8 4 4 4 4];
the result is
y{1} =
1 1 1
y{2} =
4 4
y{3} =
5 5
y{4} =
4
y{5} =
6
y{6} =
1
y{7} =
2
y{8} =
4 4 4
y{9} =
9
y{10} =
8
y{11} =
4 4 4 4