i am new in ajax. i am aware to html,php. i want to do the CRUD operation in ajax. i have created a two file
when i click on submit button it submit data and inserted in database. But it resfresh the page. please suggest me that where i made mistake.
my code as below:
index.php
<!DOCTYPE html>
<html>
<head>
<title>Ajax test</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js">
<script type="text/javascript">
var frm = $('#contactForm1');
frm.submit(function (ev) {
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
alert('ok');
}
});
ev.preventDefault();
});
</script>
</head>
<body>
<form id="contactForm1" action="insert.php" method="post">
<label>Name</label><input type="text" name="user_name"><br>
<label>Age</label><input type="number" name="user_age"><br>
<label>Course</label><input type="text" name="user_course">
<br>
<input type="submit" name="sumit" value="submit">
</form>
</body>
</html>
insert.php
<?php
$conn = mysqli_connect("localhost", "root", "" ,"aj");
$name = $_POST['user_name'];
$age = $_POST['user_age'];
$course = $_POST['user_course'];
$insertdata=" INSERT INTO test3 (name,age,course) VALUES( '$name','$age','$course' ) ";
mysqli_query($conn,$insertdata);
?>
Close the script tag
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
Use when document is ready
$( document ).ready(function() {
var frm = $('#contactForm1');
frm.submit(function (ev) {
$.ajax({
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
frm[0].reset();
alert('ok');
}
});
ev.preventDefault();
});
});
The ready event occurs when the DOM (document object model) has been loaded. Because this event occurs after the document is ready, it is a good place to have all other jQuery events and functions. Like in the example above. The ready() method specifies what happens when a ready event occurs.