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fileunixoperating-systemfilesystemsinode

Maximum file size supported by a file representation of a node?

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For a I feel like it would be 63504 Bytes because the file size would be (496/4)*512 + 16 Bytes.. But I cant seem to get that in the requested format, which leads me to believe that I attempted it wrong.

For pt b I have no Idea how to approach it.. Any help/hints would be appreciated

Solution

  • Part [a]

    Starting with 

              Extent size 1 ==> File size will be 2^0 * 512 bytes 

              Extent size 2 ==>File size will be  2^1 * 512 bytes

              Extent size 3 ==>File size will be  2^2 * 512 bytes

              ......

              Extent size 12 ==>File size will be  2^11 * 512 bytes

              Extent size x ==>File size will be  2^(x-1) * 512 bytes

    Part [b]

    Considering 512 bytes as block size,

Number of disk accesses required for getting 1,00,000 byte will be,

100000/512  = 196

    I hope it does make sense to you....