How std::bind increases number of arguments passed to a function?

I am reading a book, and there is below code :

mActionBinding[Fire].action = derivedAction<Aircraft>(
std::bind(&Aircraft::fire, _1));

the argument that is sent to derived action, will be sent two arguemnts later.

template<typename GameObject, typename Function>derived action function 
std::function<void(SceneNode&, sf::Time)> derivedAction(Function fn) 
{
    return [=](SceneNode& node, sf::Time dt) expression 
    {
        assert(dynamic_cast<GameObject *>(&node) != nullptr);

        fn(static_cast<GameObject &>(node), dt);
    };
}

the declaration of fire is this which is in Aircraft class:

class Aircraft:public SceneNode
{
public:
    void fire()
};

I have read some articles about std::bind, but honestly I haven't seen anything like this.this is much more complex.

let me sort my questions:

1-based on my reading, this std::bind has three arguments! the member function, implicit class name and _1. is it true? does this mean, when we invoke it in derivedAction,instead of static_cast<gameObject &>(node), "this" will be sent to it?

2-fire has no argument at all!(except for implicit this), so why _1 give us no error? and how "dt" will be sent to it?

I am a little confused, references gives examples of simple uses, any other information about std::bind, will be appreciated.

Solution

std::bind(&Aircraft::fire, _1)

1) There are two arguments passed to std::bind. The first argument is &Aircraft::fire, a pointer to the member function Aircraft::fire. The second argument is std::placeholders::_1, found by unqualified lookup due to the presence of a using namespace std::placeholders somewhere.

fn(static_cast<GameObject &>(node), dt)

2) The argument static_cast<GameObject &>(node) replaces the _1 placeholder. Aircraft::fire has one parameter, the implicit this, so static_cast<GameObject &>(node) is supplied as the implicit this argument to Aircraft::fire. The argument dt would replace the _2 placeholder, but since there is no _2, it is ignored.