Copy a string into another without \0

Question

I have to put a string into another without \0, I tryed a lot of ways but the string is always dirty.

char string[100];
int pos=0;

fgets(string, 99, stdin);
len = strlen(string);
printf("%d\n", len);
char array[len-1];

for(pos=0; pos<(len-1); pos++)
    {
      array[j]=string[pos];
      j++;
    }

printf("%s", string);
printf("%s", array);

In the terminal I have: dogs dogs(ENTER) 10(ENTER) dogs dogs(ENTER) dogs dogs@

I also tryed to remove \0 using another symbol but it can't see '\0' or '\n', help me plz!

Answer 1

Passing pointer to what is not a null-terminated string to %s without length specification will invoke undefined behavior. You have to specify the length to print if you hate terminating null-character for some reason.

Try this:

#include <stdio.h>
#include <string.h>

int main(void) {
  int len;

  char string[100];
  int pos=0;

  fgets(string, 99, stdin);
  len = strlen(string);
  printf("%d\n", len);
  char array[len];

  for(pos=0; pos<len; pos++)
      {
        array[pos]=string[pos];
      }

  printf("%s", string);
  printf("%*s", len, array);

  return 0;
}