How should i decode this data/these strings

I am currently trying to work through an OLD python CTF challenge, the script of the server is provided, and the idea is to send the correct data to this server,

#!/usr/bin/env python3
# from dis import dis
import socketserver
import types


class RequestHandler(socketserver.BaseRequestHandler):

    def handle(self):
        self.request.sendall(b'PyDRM Proof of Concept version 0.7\n')
        self.request.sendall(
            b'Submit the secret password to retrieve the flag:\n')
        user_input_bytes = self.request.recv(4096).strip()
        user_input = user_input_bytes.decode('utf-8', 'ignore')
        if validate_password(user_input):
            self.request.sendall(read_flag())
        else:
            self.request.sendall(b'Invalid password\n')


class RequestServer(socketserver.ThreadingMixIn, socketserver.TCPServer):
    pass


def read_flag():
    with open('flag.txt', 'rb') as fh:
        return fh.read()


def generate_validation_function():
    code_obj = types.CodeType(
        1,
        0,
        5,
        32,
        67,
        b'd\x01\x00d\x02\x00d\x03\x00d\x04\x00d\x05\x00d\x06\x00d\x05\x00d\x07'
        b'\x00d\x08\x00d\x05\x00d\t\x00d\x08\x00d\n\x00d\x01\x00d\x07\x00d\x07'
        b'\x00d\x01\x00d\x0b\x00d\x08\x00d\x07\x00d\x0c\x00d\r\x00d\x0e\x00d'
        b'\x08\x00d\x05\x00d\x0f\x00d\x03\x00d\x04\x00d\x05\x00d\x06\x00d\x05'
        b'\x00d\x07\x00g \x00}\x01\x00g\x00\x00}\x02\x00x+\x00|\x01\x00D]#\x00'
        b'}\x03\x00|\x02\x00j\x00\x00t\x01\x00t\x02\x00|\x03\x00\x83\x01\x00d'
        b'\x10\x00\x18\x83\x01\x00\x83\x01\x00\x01qs\x00Wd\x11\x00j\x03\x00|'
        b'\x02\x00\x83\x01\x00}\x04\x00|\x00\x00|\x04\x00k\x02\x00r\xb9\x00d'
        b'\x12\x00Sd\x13\x00S',
        (None, '\x87', '\x9a', '\x92', '\x8e', '\x8b', '\x85', '\x96', '\x81',
         '\x95', '\x84', '\x94', '\x8a', '\x83', '\x90', '\x8f', 34, '', True,
         False),
        ('append', 'chr', 'ord', 'join'),
        ('a', 'b', 'c', 'd', 'e'),
        'drm.py',
        'validate_password',
        5,
        b'\x00\x01$\x01$\x01\x1e\x01\x06\x01\r\x01!\x01\x0f\x01\x0c\x01\x04'
        b'\x01',
        (),
        ()
    )
    func_obj = types.FunctionType(code_obj, globals())
    return func_obj


def main():
    setattr(__import__(__name__), 'validate_password',
            generate_validation_function())
    server = RequestServer(('0.0.0.0', 8765), RequestHandler)
    try:
        server.serve_forever()
    except (SystemExit, KeyboardInterrupt):
        server.shutdown()
        server.server_close()

if __name__ == '__main__':
    main()

EDIT

I understand, what is going on to the point that a validate_password function is created by using a CodeType and FunctionType objects. I also understand that if validate_password(user_input) evaluates as True, the flag will be sent. meaning that the return type must be boolean. The documentation for CodeType along with the server script also reveals that validate_password has only one argument.

My Actual Question

The source contains compiled python bytecode. b'd\x01\x00d\x02\x00d\x03\x00d\x04\x00d\x05\x00d\x06\x00d\x05\x00d\x07'for example. I have tried numerous ways to decode/encode these strings to get some meaningful data, the only data i have managed to extract is hexadecimal.

How do i convert this data into actual code, therefore being able to reconstruct the validate_password function.

What I have Tried

SO - Python: convert string to packed hex ( '01020304' -> '\x01\x02\x03\x04' ) - I have attempted to basically do what this answer suggests but in reverse, i have either not understood it correctly, or this doesn't work

binascii.b2a_hex() - This is how I managed to convert the strings into hex, like i stated earlier however, i cannot yield utf-8 data from this hex.

struct.unpack() - Had some success with this method, yet am at a loss of what the data would mean in the context of the validate_password function, I can only get integers with this method. (Unless i have misunderstood)

Solution

Riffing off of das-g's answer, this code works. Sorta.

import uncompyle6
import types
code_obj = types.CodeType(
        1, 0, 5, 32, 67, b'd\x01\x00d\x02\x00d\x03\x00d\x04\x00d\x05\x00d\x06\x00d\x05\x00d\x07'
        b'\x00d\x08\x00d\x05\x00d\t\x00d\x08\x00d\n\x00d\x01\x00d\x07\x00d\x07'
        b'\x00d\x01\x00d\x0b\x00d\x08\x00d\x07\x00d\x0c\x00d\r\x00d\x0e\x00d'
        b'\x08\x00d\x05\x00d\x0f\x00d\x03\x00d\x04\x00d\x05\x00d\x06\x00d\x05'
        b'\x00d\x07\x00g \x00}\x01\x00g\x00\x00}\x02\x00x+\x00|\x01\x00D]#\x00'
        b'}\x03\x00|\x02\x00j\x00\x00t\x01\x00t\x02\x00|\x03\x00\x83\x01\x00d'
        b'\x10\x00\x18\x83\x01\x00\x83\x01\x00\x01qs\x00Wd\x11\x00j\x03\x00|'
        b'\x02\x00\x83\x01\x00}\x04\x00|\x00\x00|\x04\x00k\x02\x00r\xb9\x00d'
        b'\x12\x00Sd\x13\x00S',
        (None, '\x87', '\x9a', '\x92', '\x8e', '\x8b', '\x85', '\x96', '\x81',
         '\x95', '\x84', '\x94', '\x8a', '\x83', '\x90', '\x8f', 34, '', True,
         False),
        ('append', 'chr', 'ord', 'join'),
        ('a', 'b', 'c', 'd', 'e'),
        'drm.py',
        'validate_password',
        5,
        b'\x00\x01$\x01$\x01\x1e\x01\x06\x01\r\x01!\x01\x0f\x01\x0c\x01\x04'
        b'\x01',
        freevars=(),
        cellvars=()
    )

import sys
uncompyle6.main.uncompyle(3.5, code_obj, sys.stdout)

What's missing here is that this code is really wrapped inside a function that takes an "a" parameter.

I won't spoil the fun giving the answer. Instead:

Run the above program.
Wrap the output in something like:
def drm(a): # Output from run above.