I need to create request to access to the XML services, it should be processed through a HTTP. Ass says in documentation I have to send "4 associated parameters and this parameters will work as identification and will provide the request". This parameters should look like strings:
"codes=12345"
"user=user12345"
"password=pass12345"
"partner=part12345"
According documentation i have two systems for sending the XML file of the request:
1 Through an URL coded in MIME format application/x-www-form- urlencoded: URL (“urlfile”)
2 By entering the data directly in a variable, coded in MIME format application/x-www-form-urlencoded: Directly in a variable (“xml”).
According to this my request data looks like this:
data='
<?xml version="1.0" encoding="ISO-8859-1" ?>
<!DOCTYPE petition SYSTEM "http://xml.example.com/xml/dtd/xml.dtd">
<petition>
<number>Country request</number>
<partner>Company</partner>
<type>5</type>
</petition>'
I create this request using python library urllib2. So here is my code:
request = urllib2.Request(url, data)
request.add_header("codes=12345", "user=user12345", "password=pass12345", "partner=part12345")
But i got an error:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: add_header() takes exactly 3 arguments (5 given)
So i changed header on this:
header = {'codes':'12345','user':'user12345','password':'pass12345','partner':'part12345'}
And this is how looks like my code after that:
request = urllib2.Request(url, data, header)
response_xml = urllib2.urlopen(request)
response = response_xml.read()
print(response)
But I got response such if i not authenticated user. What i'm doing wrong? Thank You!
Try this:
from urllib import urlencode
from urllib2 import urlopen
args = {'codes':'12345','user':'user12345','password':'pass12345','partner':'part12345'}
conn = urlopen(url,urlencode(args))
data = conn.read()
conn.close()
print(data)