I am trying to compare the files in two directories but I am having trouble getting my stat command to work properly, I can get it to work from the command line using the same syntax as I have here.
# Usage: compdir <base_dir> <modified_dir>
# Handle MODIFIED and REMOVED files
for i in "${arr1[@]}"
do
REMOVED=1
for j in "${arr2[@]}"
do
if [ $i = $j ]; then
# take time stamps
dir1="$1"
dir2="$2"
stamp1=stat --format %Y "$i" <--------- THIS LINE
stamp2=stat --format %Y "$j"
if [[ $stamp1 > $stamp2 ]] ; then
echo "$j MODIFIED"
fi
REMOVED=0
break
fi
done
if [ $REMOVED -eq 1 ]; then
echo $i REMOVED
fi
done
# handle NEW files
for j in "${arr2[@]}"
do
NEW=1
for i in "${arr1[@]}"
do
if [ $j = $i ]; then
NEW=0
break
fi
done
if [ $NEW -eq 1 ]; then
echo "$j NEW"
fi
done
On the line marked with a <------- and the line below I get the error --format: command not found. I am assuming this is because I am in the base directory and not in the subdirectories. Since the arguments passed are the names of the directories I've tried doing something like "$1/$i" to get the line to work but have had no luck.
You cannot just assign a command to a variable, you have to do it in a subshell using $()
or ``. Like here:
Option 1:
stamp1=$(stat --format %Y "$i")
Option 2:
stamp1=`stat --format %Y "$i"`
I personally prefer option 1 (subshell)
Addendum: As stated in the comment by sp asic (thx), use $()
as the backticks are the legacy syntax, see: http://mywiki.wooledge.org/BashFAQ/082