I am taking over a laravel project that uses elixir to compile various sass, coffeescript, and javascript files:
elixir(function(mix) {
mix.sass('main.scss')
.coffee(['methods.coffee', 'details.coffee', 'cars.coffee', 'context-menu.coffee', 'content.coffee', 'projects.coffee', 'main.coffee'])
.styles(['main.css'], 'public/css/all.css', 'public/css')
.scripts(['app.js'], 'public/js/all.js', 'public/js')
.version(['css/all.css', 'js/all.js']);
});
My questions:
What is the destination of the files below after they are compiled?
.coffee(['methods.coffee', 'details.coffee', 'cars.coffee', 'context-menu.coffee', 'content.coffee', 'projects.coffee', 'main.coffee'])
Does the line below compile the app.js
file as all.js
and store it in public/js
?
.scripts(['app.js'], 'public/js/all.js', 'public/js')
Similarly, does the line below compile the main.css
file as all.css
and store it in public/css
?
.styles(['main.css'], 'public/css/all.css', 'public/css')
Thanks in advance!
By default, the task will place the compiled in:
UPDATE
To change the output path just pass a second argument to the method
e.g.
mix.styles([
'bundle.css'
], 'public/css/aloha');