Following on form this excellent set of answers on how to define union types in Scala. I've been using the Miles Sabin definition of Union types, but one questions remains.
How do you work with these if the type isn't know until Runtime? For example:
trait inv[-A] {}
type Or[A,B] = {
type check[X] = (inv[A] with inv[B]) <:< inv[X]
}
case class Foo[A : (Int Or String)#check](a: A)
Foo(1) // Foo[Int] = Foo(1)
Foo("hi") // Foo[String] = Foo(hi)
Foo(2.0) // Error!
This example works since the parameter A is know at compile time, and calling Foo(1) is really calling Foo[Int](1). However, what do you do if parameter A isn't known until runtime? Maybe you're paring a file that contains the data for Foo's, in which case the type parameter of Foo isn't know until you read the data. There's no easy way to set parameter A in this case.
The best solutions I've been able to come up with are:
Pattern Match on the data you've read and then create different Foo's based that type. In my case this isn't feasible because my case-class actually contains dozens of union types, so there'd be hundreds of combinations of types to pattern match.
Cast the type you've just read to be (String or Int), so you have a single type to pass around, that passes the Type Class constraint when you create Foo with it. Then return Foo[_] instead. This puts the onus back on the Foo user to work out the type of each field (since they'll appear to be type Any), but at least it defers having to know the type until the field is actually used, in which case a pattern match seems more tractable.
The second solution looks like this:
def parseLine: Any // Parses data point, but can be either a String or
// Int, so returns Any.
def mkFoo: Foo[_] = {
val a = parseLine.asInstanceOf[Int with String]
Foo(a) // Passes type constraint now
}
In practice I've ended up using the second solution, but I'm wondering if there's something better I can do?
Another way to state the problem is: What does it mean to return a Union Type? Functions can only return a single type, and the trickery we use with Miles Sabin union types is only useful for the types you pass in, not for the types you return.
PS. For context, why this is a problem in my case is that I'm generating a set of case-classes from a Json schema file. Json naturally supports union types, so I would like to make my case classes reflect that too. This works great in one direction: users creating case-classes to be serialized out to Json. But gets sticky in the other direction: user's parsing Json files to have a set of populated case classes returned to them.
The "standard" Scala solution to this problem is to use an ordinary discriminated-union type (ie, to forego true union types altogether):
sealed trait Foo
case class IntFoo(x: Int) extends Foo
case class StringFoo(x: String) extends Foo
This reflects the fact that, as you observe, the particular type of the member is a runtime value; the JVM type-tag of the Foo instance provides this runtime value.
Miles Sabin's implementation of union types is very clever, but I'm not sure if it provides any practical benefit, because it only restricts the type of thing that can go into a Foo, but provides the user of a Foo with no computable version of that restriction, in the way a match provides you with a computable version of the sealed trait. In general, for a restriction to be useful, it needs two sides: a check that only the right things are put in, and an extractor (aka an eliminator) that allows the same right things to come out the other end.
Perhaps if you gave some explanation of why you're looking for a purer union type it would illuminate whether regular discriminated unions are sufficient or if you really need something more.