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swiftbuttonuiactionsheet

Move destructiveButtonTitle to bottom of UIActionSheet

I wish to move the cancel button to the bottom of my actionsheet, to be the last button available to the user. I have this code:

func openImagePicker(
    actionSheetTitle:String="Choose Image Source",
    cancelTitle:String="Cancel",
    cameraTitle:String="Camera",
    galleryTitle:String="Gallery",
    isImage:Bool=true,
    isMultipleSelection:Bool=false,
    completeHandler:(success:Bool,arrAssert:[TCAsset])->Void,
    failurer:((error:String)->(Void))?=nil)
{

    let actionSheet=UIActionSheet(title: actionSheetTitle, delegate:self, cancelButtonTitle:nil, destructiveButtonTitle:cancelTitle,otherButtonTitles: cameraTitle, galleryTitle)

    if UIDevice.currentDevice().userInterfaceIdiom == .Phone
    {
        actionSheet.showInView(UIApplication.sharedApplication().keyWindow!)
    }
    else
    {
        let appDel = UIApplication.sharedApplication().delegate as? AppDelegate


        actionSheet.showInView((appDel?.window?.rootViewController?.view)!)
    }

Which currently displays the actionsheet like this:

enter image description here

How can I make it so the cancel button is the last button on the list?

Thanks :)

Solution

  • I feel that there's a very simple answer to this:

    You can use destructiveButtonIndex to set the index of the destructiveButton to wherever you want.

    actionSheet.destructiveButtonIndex = 2;