I am using Fortran 90 and the Intel compiler. I am very confused using a function in a subroutine. My code is (I deleted everything unimportant):
program test
INTEGER :: seed=5
REAL :: nor_ran_number1, nor_ran_number2
CALL Box_Muller_transform(seed,nor_ran_number1,nor_ran_number2)
end program test
double precision function grnd(SEED)
grnd=5
return
end
SUBROUTINE Box_Muller_transform (seed,nor_ran_number1,nor_ran_number2)
implicit none
INTEGER, INTENT(in) :: seed
REAL, INTENT(out) :: nor_ran_number1, nor_ran_number2
nor_ran_number1 = grnd(seed)
nor_ran_number2 = grnd(seed)
end SUBROUTINE Box_Muller_transform
The compiler returns:
error #6404: This name does not have a type, and must have an explicit
type. [GRND]
nor_ran_number1 = grnd(seed)
------------------^
I found this and understand that the function "grad" is not visible inside "Box_Muller_transform". However then I would expect the following code to produce the same error:
program test
INTEGER ::a=5, b
call sub(a,b)
write(*,*) b
end program
SUBROUTINE sub(a,b)
INTEGER, INTENT(in) ::a
INTEGER, INTENT(out) ::b
b = fun(a)
end subroutine sub
function fun(a)
INTEGER :: fun
INTEGER :: a
fun = a*a
end function fun
But this is working. I would be very happy if someone could point out the difference and explain the simplest way to solve this problem.
Functions must have their return value defined. Since you are using implicit none
in your first example, the type of the return value of grnd
must be defined explicitly:
SUBROUTINE Box_Muller_transform (seed,nor_ran_number1,nor_ran_number2)
implicit none
INTEGER, INTENT(in) :: seed
REAL, INTENT(out) :: nor_ran_number1, nor_ran_number2
double precision :: grnd
nor_ran_number1 = grnd(seed)
nor_ran_number2 = grnd(seed)
end SUBROUTINE Box_Muller_transform
In the second example, you have not specified implicit none
in sub
, therefore fun
is assumed to be of (implicit) type real
. The compiler seems to silently cast this to integer.