NodeJS exec() command for both Windows and Ubuntu

Question

Using NodeJS, NPM, and Gulp.

I want to build a gulp task to run JSDoc that works on Ubuntu and Windows.

This works on Ubuntu...

var exec = require('child_process').exec;

return function(cb) {
  exec('node node_modules/.bin/jsdoc -c jsdoc-conf.json', function(err, stdout, stderr) {
    cb(err);
  });
};

And this works on Windows...

var exec = require('child_process').exec;

return function(cb) {
  exec('node_modules\\.bin\\jsdoc -c jsdoc-conf.json', function(err, stdout, stderr) {
    cb(err);
  });
};

Needless to say, neither works on the other. How do others solve this type of problem?

Answer 1

Node has process.platform, which... "returns a string identifying the operating system platform on which the Node.js process is running. For instance darwin, freebsd, linux, sunos or win32"

https://nodejs.org/api/process.html#process_process_platform

var exec = require('child_process').exec;

return function(cb) {
  if (process.platform === 'win32') {
    // Windows OS
  } else {
    // everything else
  }
};