Correct way to check Javac version in BASH script

Question

I am trying to get the javac version in a bash script (intended for apks manipulation and builds).

I found a way to get the java version which may be similar but not the same (it does not work for javac).

P.S.: Currently working on OS X but should also work on Linux.

EDIT: PS: Some environments may not have javac in the PATH

Thanks!

Answer 1

Try this function that supports both cases, when javac is or is not in PATH variable

showJavacVersion() 
{
    x="h"
    {
        x=$(type -p javac)
    } >&-
    if [ -n "$x" ]; then
        _javac=javac
    elif [[ -n "$JAVA_HOME" ]] && [[ -x "$JAVA_HOME/bin/javac" ]];  then
        _javac="$JAVA_HOME/bin/javac"
    fi
    if [[ "$_javac" ]]; then
        version=$("$_javac" -version 2>&1 | awk -F ' ' '/javac/ {print $2}')
        echo $version
    else
        echo javac not found
    fi
}

Simply call it this way

showJavacVersion

Hope it helps!