C - BitArray - Set single bit of uint64_t

Question

I'm currently working on a project, in which I need bit sets. I'm using an array of uint64_t's for the bitset.

My current problem is, that whenever I want to set or check a bit I need to do an operation like this:

uint64_t index = 42;
bArr[index/64] |= (((uint64_t)1)<<(index%64)); 

I can rewrite the division and modulo with some clever and and bitshift operations as well, but I'm concerned about the cast of 1. I need this cast, since otherwise the 1 is seen as a 32-bit unit. As seen in this example - you get wrong output without a cast:

uint64_t bArr[4];                           // 256 bits 
bArr[0] = bArr[1] = bArr[2] = bArr[3] = 0;  // Set to 0

uint64_t i = 255;
bArr[i/64] = (bArr[i/64] | (((uint64_t)1)<<(i%64))); 

uint32_t i2;
for (i2 = 0; i2 < 256; i2++) {
  if ((bArr[i2/64] & (((uint64_t)1)<<(i2%64))) != 0) {
    printf("bArray[%" PRIu32 "] = 1\n", i2);
  }
}

Can I get around this cast in a clever way? I was thinking that the performance is probably suffering from a cast at every read/write...

Answer 1

The result type of << operator is the type of the left operand (after integer promotions) that's why you need to use the correct type: 1 is of type int but you need type uint64_t.

You can use either:

(uint64_t) 1

or

UINT64_C(1)  /* you have to include <stdint.h> */

or

1ULL  

(for the last one assuming unsigned long long is 64-bit in your system which is very likely).

But they are all equivalent: all these expressions are integer constant expressions and their value is computed at compile time and not at run time.